For what values of t will there be a profit? (that is, p>0) Algebra -> College -> Linear Algebra -> SOLUTION: assume that the profit p made when t units are sold, t>0 is given by p(t)=t^2-24t+108.
Accounting Rate of Return. You may use the attached spreadsheet to help you complete this activity, but you are not required to do so. You will find the spreadsheet by clicking on the link in the drop-down menu above. Each of the following scenarios is independent. Assume that
* COPPER PRICE: Three-month copper on the London Metal Exchange ended up 1.5 percent at $7,0454 a tonne, crossing the psychologically important $7,000 mark and hitting its highest since mid ...
rate in minus the rate out) of water is f t t( )= 20 1(2) liters per minute. a) For 0 3 t , find the change in the amount of water in the reservoir. b) If the tank has 200 liters of water at time t=0, determine how many liters are in the tank at t=3.
AP Calculus AB Semester One Exam Review 2014-2015 2014-2015 AP Calculus AB Semester One Exam Review (edited 12/4/2014) Page 3 10. TRUE or FALSE, given the graph of f to the right. a. 1 lim ( ) x fx o exists. ____ b . 2 lim ( ) x fx o exists. ____ c. f is continuous over the interval . _____ d. f is differentiable over the interval .
Start studying Chapter 23- Energy and Mineral Resources. Learn vocabulary, terms, and more with flashcards, games, and other study tools.
Suppose that the profit on a copper mine at time t is given by πt=pqt cqt2 kst , where p, c and k are exogenous constants, qt is the amount of copperextracted in period t, and st is the total amount of silver extracted in all periods before t.
Suppose that the profit on an aluminum mine at time t is given by o = pqt cqt 2 kst, where p, c, and k are exogenous constants, qt is the amount of aluminum extracted in period t, and st is the total amount of aluminum extracted in all periods before t. The evolution of
70 t to 6,900 t, and global London Metal Exchange Ltd. stocks of tin decreased by 1,930 t to 4,800 t. Figure 2. Average monthly prices for tin from September 2013 through September 2015. Source: Platts Metals Week. Wolf Minerals Ltd. officially opened the Hemerdon tungsten and tin project in Devon, United Kingdom, in September 2015.
P = t^2 32t + 255. We need to find the non-negative solution for the quadratic equation: t^2 32t + 255 = 0..... click here to see the equation solved for t..... t1 = 15 units. t2 = 17 units. The break-even point happens for 15 units produced as well as for 17 units produced.